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NCERT Solutions for Class 11 Chemistry Chapter 2 Structure of Atom

NCERT Solutions for Class 11 Chemistry Chapter 2 Structure of Atom covers the discovery of sub-atomic particles, atomic models, the dual nature of matter, Bohr's model, quantum mechanical model, and electronic configuration.

Overview of Topics & Subtopics (Click to Jump)

1. Discovery of Sub-atomic Particles

Short Note:

• Electron (discovered by J.J. Thomson, via cathode ray experiments): negatively charged, e/m = 1.75 × 10&sup8; C/g.

• Proton (discovered by Goldstein, via anode/canal rays): positively charged particle present in the nucleus.

• Neutron (discovered by Chadwick): neutral particle present in the nucleus, mass nearly equal to that of a proton.

2. Atomic Models

Short Note:

• Rutherford's Nuclear Model: based on the alpha-particle scattering experiment, proposed that most of the atom's mass and all positive charge is concentrated in a tiny, dense nucleus, with electrons revolving around it.

• Bohr's Model: electrons revolve in fixed circular orbits (energy levels) without radiating energy; energy is absorbed or emitted only when an electron jumps between orbits, explaining the hydrogen line spectrum.

3. Dual Nature of Matter and Quantum Mechanical Model

Short Note:

• de Broglie's Equation: λ = h/mv, showing that matter (like light) has both wave and particle nature.

• Heisenberg's Uncertainty Principle: it is impossible to determine simultaneously, with absolute accuracy, both the position and momentum of a microscopic particle like an electron.

• The Quantum Mechanical Model describes electrons in terms of orbitals (regions of maximum probability of finding an electron), characterised by four quantum numbers: principal (n), azimuthal (l), magnetic (ml), and spin (ms).

4. Electronic Configuration of Atoms

Short Note:

• Aufbau Principle: electrons are filled into orbitals in order of increasing energy.

• Pauli Exclusion Principle: no two electrons in an atom can have the same set of all four quantum numbers.

• Hund's Rule of Maximum Multiplicity: electrons are distributed singly among orbitals of the same subshell before pairing up.

NCERT Textbook Exercise Questions

Calculate the number of electrons, protons and neutrons in an atom of 35Cl17.
Answer: Atomic number Z = 17, so number of protons = 17 = number of electrons (neutral atom). Mass number A = 35, so number of neutrons = A − Z = 35 − 17 = 18.
Calculate the energy associated with the first orbit of the hydrogen atom.
Answer: Using Bohr's formula En = −2.18 × 10−18(Z²/n²) J. For hydrogen, Z=1, n=1: E1 = −2.18 × 10−18 J.
What is the maximum number of electrons that can be associated with the principal quantum number n = 3?
Answer: Total electrons in a shell = 2n² = 2(3)² = 18. So the n=3 shell can hold a maximum of 18 electrons.
Write the electronic configuration of Cr (Z=24) and explain any exception observed.
Answer: Expected configuration by Aufbau would be [Ar]3d&sup4;4s², but the actual configuration is [Ar]3d&sup5;4s¹, because a half-filled d-subshell (3d&sup5;) provides extra stability.
How many sub-shells are associated with n = 4, and what are the possible values of l for n = 4?
Answer: For n=4, l can take values 0, 1, 2, 3, corresponding to 4 sub-shells: 4s (l=0), 4p (l=1), 4d (l=2), and 4f (l=3).
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Class 11 › Chemistry › Structure of Atom
Chapter notesRead the chapterPractice MCQsCheck what you rememberChapter test10 questions on one pageOnline testTest 1, 2 and 3, one question at a timePYQPrevious year questionsStudy materialPDF notes
Topics in this chapter: Subatomic Particles & Early Atomic ModelsElectromagnetic Radiation, Planck's Quantum Theory & Bohr's ModelDual Nature of Matter & Heisenberg's Uncertainty PrincipleQuantum Mechanical Model, Quantum Numbers & Electronic Configuration